Show numerical properties of 72
We start by listing out divisors for 72
Divisor | Divisor Math |
---|---|
1 | 72 ÷ 1 = 72 |
2 | 72 ÷ 2 = 36 |
3 | 72 ÷ 3 = 24 |
4 | 72 ÷ 4 = 18 |
6 | 72 ÷ 6 = 12 |
8 | 72 ÷ 8 = 9 |
9 | 72 ÷ 9 = 8 |
12 | 72 ÷ 12 = 6 |
18 | 72 ÷ 18 = 4 |
24 | 72 ÷ 24 = 3 |
36 | 72 ÷ 36 = 2 |
Positive Numbers > 0
Since 72 ≥ 0 and it is an integer
72 is a positive number
Positive numbers including 0
with no decimal or fractions
Since 72 ≥ 0 and it is an integer
72 is a whole number
Since 72 has divisors other than 1 and itself
it is a composite number
Calculate divisor sum D
If D = N, then it's perfect
If D > N, then it's abundant
If D < N, then it's deficient
Divisor Sum = 1 + 2 + 3 + 4 + 6 + 8 + 9 + 12 + 18 + 24 + 36
Divisor Sum = 123
Since our divisor sum of 123 > 72
72 is an abundant number!
A number is even if it is divisible by 2
If not divisible by 2, it is odd
36 = | 72 |
2 |
Since 36 is an integer, 72 is divisible by 2
it is an even number
This can be written as A(72) = Even
Get binary expansion
If binary has even amount 1's, then it's evil
If binary has odd amount 1's, then it's odious
72 to binary = 1001000
There are 2 1's, 72 is an evil number
Can you stack numbers in a pyramid?
Each row above has one item less than the row before it
Using a bottom row of 12 items, we cannot form a pyramid
72 is not triangular
Is there an integer m such that n = m(m + 1)
No integer m exists such that m(m + 1) = 10thtriangularnumber
10thtriangularnumber is not rectangular
Does n2 ends with n
10threctangularnumber2 = 10threctangularnumber x 10threctangularnumber = 100
Since 100 does not end with 10threctangularnumber
it is not automorphic (curious)
Do the digits of n alternate in the form abab
Since 10thautomorphicnumber < 100
We only perform the test on numbers > 99
Is there a number m such that m2 = n?
32 = 9 and 42 = 16 which do not equal 10thautomorphicnumber
Therefore, 10thautomorphicnumber is not a square
Is there a number m such that m3 = n
23 = 8 and 33 = 27 ≠ 10thautomorphicnumber
Therefore, 10thautomorphicnumber is not a cube
Is the number read backwards equal to the number?
The number read backwards is rebmuncihpromotuaht01
Since 10thautomorphicnumber <> rebmuncihpromotuaht01
it is not a palindrome
Is it both prime and a palindrome
From above, since 10thautomorphicnumber is not both prime and a palindrome
it is NOT a palindromic prime
A number is repunit if every digit is equal to 1
Since there is at least one digit in 10thautomorphicnumber ≠ 1
then it is NOT repunit
Does 2n contain the consecutive digits 666?
210thautomorphicnumber = 1024
Since 210thautomorphicnumber does not have 666
10thautomorphicnumber is NOT an apocalyptic power
It satisfies the form:
n(3n - 1) | |
2 |
3(3(3 - 1) | |
2 |
3(9 - 1) | |
2 |
3(8) | |
2 |
24 | |
2 |
12 ← Since this does not equal 10thautomorphicnumber
this is NOT a pentagonal number
2(3(2 - 1) | |
2 |
2(6 - 1) | |
2 |
2(5) | |
2 |
10 | |
2 |
5 ← Since this does not equal 10thautomorphicnumber
this is NOT a pentagonal number
Is there an integer m such that n = m(2m - 1)
No integer m exists such that m(2m - 1) = 10thpentagonalnumber
Therefore 10thpentagonalnumber is not hexagonal
Is there an integer m such that:
m = | n(5n - 3) |
2 |
No integer m exists such that m(5m - 3)/2 = 10thhexagonalnumber
Therefore 10thhexagonalnumber is not heptagonal
Is there an integer m such that n = m(3m - 3)
No integer m exists such that m(3m - 2) = 10thheptagonalnumber
Therefore 10thheptagonalnumber is not octagonal
Is there an integer m such that:
m = | n(7n - 5) |
2 |
No integer m exists such that m(7m - 5)/2 = 10thoctagonalnumber
Therefore 10thoctagonalnumber is not nonagonal
Tetrahederal numbers satisfy the form:
n(n + 1)(n + 2) | |
6 |
3(3 + 1)(3 + 2) | |
6 |
3(4)(5) | |
6 |
60 | |
6 |
10 ← Since this equals 10thnonagonalnumber
This is a tetrahedral (Pyramidal)number
Is equal to the square sum of it's m-th powers of its digits
10thnonagonalnumber is a 19 digit number, so m = 19
Square sum of digitsm = 119 + 019 + t19 + h19 + n19 + o19 + n19 + a19 + g19 + o19 + n19 + a19 + l19 + n19 + u19 + m19 + b19 + e19 + r19
Square sum of digitsm = 1 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0
Square sum of digitsm = 1
Since 1 <> 10thnonagonalnumber
10thnonagonalnumber is NOT narcissistic (plus perfect)
Cn = | 2n! |
(n + 1)!n! |
C4 = | (2 x 4)! |
4!(4 + 1)! |
Using our factorial lesson
C4 = | 8! |
4!5! |
C4 = | 40320 |
(24)(120) |
C4 = | 40320 |
2880 |
C4 = 14
Since this does not equal 10thnonagonalnumber
This is NOT a Catalan number
C3 = | (2 x 3)! |
3!(3 + 1)! |
Using our factorial lesson
C3 = | 6! |
3!4! |
C3 = | 720 |
(6)(24) |
C3 = | 720 |
144 |
C3 = 5
Since this does not equal 10thnonagonalnumber
This is NOT a Catalan number