Evaluate the following logarithmic expression
logarithmof500
Evaluate logof500
You didn't enter a base
We'll do bases e and 2-10
Evaluate loge(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = e and x = 500, we have:
| loge(500) = | Ln(500) |
| Ln(e) |
Ln(e) = 1
loge(500) = 6.2146080984222
Evaluate log2(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 2 and x = 500, we have:
| log2(500) = | Ln(500) |
| Ln(2) |
log2(500) = 8.9657842846621
Evaluate log3(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 3 and x = 500, we have:
| log3(500) = | Ln(500) |
| Ln(3) |
log3(500) = 5.6567800692967
Evaluate log4(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 4 and x = 500, we have:
| log4(500) = | Ln(500) |
| Ln(4) |
log4(500) = 4.482892142331
Evaluate log5(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 5 and x = 500, we have:
| log5(500) = | Ln(500) |
| Ln(5) |
log5(500) = 3.8613531161468
Evaluate log6(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 6 and x = 500, we have:
| log6(500) = | Ln(500) |
| Ln(6) |
log6(500) = 3.4684388195809
Evaluate log7(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 7 and x = 500, we have:
| log7(500) = | Ln(500) |
| Ln(7) |
log7(500) = 3.1936768002568
Evaluate log8(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 8 and x = 500, we have:
| log8(500) = | Ln(500) |
| Ln(8) |
log8(500) = 2.988594761554
Evaluate log9(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 9 and x = 500, we have:
| log9(500) = | Ln(500) |
| Ln(9) |
log9(500) = 2.8283900346483
Evaluate log10(500) using the Change of Base Formula
The formula for the change of base rule in logb(x) is as follows:
| logb(x) = | Ln(x) |
| Ln(b) |
Given b = 10 and x = 500, we have:
| log10(500) = | Ln(500) |
| Ln(10) |
log10(500) = 2.698970004336
Final Answer
log2(500) = 8.9657842846621
log3(500) = 5.6567800692967
log4(500) = 4.482892142331
log5(500) = 3.8613531161468
log6(500) = 3.4684388195809
log7(500) = 3.1936768002568
log8(500) = 2.988594761554
log9(500) = 2.8283900346483
log10(500) = 2.698970004336
