9 hundreds
Hundred-Groups = 100 + 100 + 100 + 100 + 100 + 100 + 100 + 100 + 100
Hundred-Groups = 900
0 tens
Ten-Groups =
Ten-Groups = 0
0 ones
900 = 900 Hundreds + 0 Tens + 0 ones
900 = 900 + 0 + 0
Show numerical properties of 900
900
nine hundred
Decompose 900
Each digit in the whole number represents a power of 10:
Take the whole number portion on the left side of the decimal
Expanded Notation of 900 = (9 x 102) + (0 x 101) + (0 x 100)
Expanded Notation of 900 = (9 x 100) + (0 x 10) + (0 x 1)
900 = 900 + 0 + 0
900 = 900 <---- Correct!
Make blocks of 5
1 tally mark = |
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Define an ordinal number
A position in a list
900th
Calculate the digit sum of 900
Calculate the reduced digit sum of 900
Digit Sum → 9 + 0 + 0 = 9
Since our digit sum ≤ 9:
we have our reduced digit sum
Digit Sum → 9 + 0 + 0 = 9
Calculate the digit product of 900
Digit Product = Value when you multiply
all the digits of a number together.
We multiply the 3 digits of 900 together
Digit product of 900 = 9 * 0 * 0
Digit product of 900 = 0
Opposite of 900 = -(900)
Opposite of = -900
Place value describes each digit
9 is our hundreds digit
This means we have 9 sets of hundreds
0 is our tens digit
This means we have 0 sets of tens
0 is our ones digit
This means we have 0 sets of ones
9 is our hundreds digit
0 is our tens digit
0 is our ones digit
When ey = x and e = 2.718281828459
We have Ln(x) = loge(x) = y
Ln(900) = loge(900) = 6.8023947633243
Is 900 divisible by:
2,3,4,5,6,7,8,9,10,11
Last digit ends in 0,2,4,6,8
The last digit of 900 is 0
Since 0 is equal to 0,2,4,6,8:
then 900 is divisible by 2
Sum of the digits is divisible by 3
The sum of the digits for 900 is 9 + 0 + 0 = 9
Since 9 is divisible by 3:
Then 900 is divisible by 3
Take the last two digits
Are they divisible by 4?
The last 2 digits of 900 are 00
Since 00 is divisible by 4:
Then 900 is divisible by 4
Number ends with a 0 or 5
The last digit of 900 is 0
Since 0 is equal to 0 or 5:
Then 900 is divisible by 5
Divisible by both 2 and 3
Since 900 is divisible by 2 and 3:
Then 900 is divisible by 6
Multiply each respective digit by 1,3,2,6,4,5
Work backwards
Repeat as necessary
0(1) + 0(3) + 9(2) = 19
Since 19 is not divisible by 7:
Then 900 is not divisible by 7
Take the last three digits
Are they divisible by 8
The last 3 digits of 900 are 900
Since 900 is not divisible by 8:
Then 900 is not divisible by 8
Sum of digits divisible by 9
The sum of the digits for 900 is 9 + 0 + 0 = 9
Since 9 is divisible by 9:
Then 900 is divisible by 9
Ends with a 0
The last digit of 900 is 0
Since 0 is equal to 0:
Then 900 is divisible by 10
Σ odd digits - Σ even digits = 0
or 900 is a multiple of 11
900
9 + 0
Odd Sum = 9
900
0
Even Sum = 0
Δ = Odd Sum - Even Sum
Δ = 9 - 0
Δ = 9
Because Δ / 11 = 81.818181818182:
Then 900 is NOT divisible by 11
900 is divisible by
(2,3,4,5,6,9,10)