1 hundreds
Hundred-Groups = 100
Hundred-Groups = 100
8 tens
Ten-Groups = 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10
Ten-Groups = 80
0 ones
180 = 100 Hundreds + 80 Tens + 0 ones
180 = 100 + 80 + 0
Show numerical properties of 180
180
one hundred eighty
Decompose 180
Each digit in the whole number represents a power of 10:
Take the whole number portion on the left side of the decimal
Expanded Notation of 180 = (1 x 102) + (8 x 101) + (0 x 100)
Expanded Notation of 180 = (1 x 100) + (8 x 10) + (0 x 1)
180 = 100 + 80 + 0
180 = 180 <---- Correct!
Make blocks of 5
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Define an ordinal number
A position in a list
180th
Calculate the digit sum of 180
Calculate the reduced digit sum of 180
Digit Sum → 1 + 8 + 0 = 9
Since our digit sum ≤ 9:
we have our reduced digit sum
Digit Sum → 1 + 8 + 0 = 9
Calculate the digit product of 180
Digit Product = Value when you multiply
all the digits of a number together.
We multiply the 3 digits of 180 together
Digit product of 180 = 1 * 8 * 0
Digit product of 180 = 0
Opposite of 180 = -(180)
Opposite of = -180
Place value describes each digit
1 is our hundreds digit
This means we have 1 sets of hundreds
8 is our tens digit
This means we have 8 sets of tens
0 is our ones digit
This means we have 0 sets of ones
1 is our hundreds digit
8 is our tens digit
0 is our ones digit
When ey = x and e = 2.718281828459
We have Ln(x) = loge(x) = y
Ln(180) = loge(180) = 5.1929568508902
Is 180 divisible by:
2,3,4,5,6,7,8,9,10,11
Last digit ends in 0,2,4,6,8
The last digit of 180 is 0
Since 0 is equal to 0,2,4,6,8:
then 180 is divisible by 2
Sum of the digits is divisible by 3
The sum of the digits for 180 is 1 + 8 + 0 = 9
Since 9 is divisible by 3:
Then 180 is divisible by 3
Take the last two digits
Are they divisible by 4?
The last 2 digits of 180 are 80
Since 80 is divisible by 4:
Then 180 is divisible by 4
Number ends with a 0 or 5
The last digit of 180 is 0
Since 0 is equal to 0 or 5:
Then 180 is divisible by 5
Divisible by both 2 and 3
Since 180 is divisible by 2 and 3:
Then 180 is divisible by 6
Multiply each respective digit by 1,3,2,6,4,5
Work backwards
Repeat as necessary
0(1) + 8(3) + 1(2) = 27
Since 27 is not divisible by 7:
Then 180 is not divisible by 7
Take the last three digits
Are they divisible by 8
The last 3 digits of 180 are 180
Since 180 is not divisible by 8:
Then 180 is not divisible by 8
Sum of digits divisible by 9
The sum of the digits for 180 is 1 + 8 + 0 = 9
Since 9 is divisible by 9:
Then 180 is divisible by 9
Ends with a 0
The last digit of 180 is 0
Since 0 is equal to 0:
Then 180 is divisible by 10
Σ odd digits - Σ even digits = 0
or 180 is a multiple of 11
180
1 + 0
Odd Sum = 1
180
8
Even Sum = 8
Δ = Odd Sum - Even Sum
Δ = 1 - 8
Δ = -7
Because Δ / 11 = 16.363636363636:
Then 180 is NOT divisible by 11
180 is divisible by
(2,3,4,5,6,9,10)