Show all factor pairs, prime factorization,
sum of factors (divisors), aliquot sum,
and prime power decomposition of 8
1) 0 < Factor Pairs ≤ 8
2) The factor pair product = 8
Number | Factor Pairs | Factor Pairs Sum |
---|---|---|
8 | 1 x 8 | 9 |
8 | 2 x 4 | 6 |
There are 2 factor pairs of 8
1, 2, 4, 8
τ(8) = 4
1
2, 4, 8
Proper factors are all factors except for the number itself
in this case 8
1, 2, 4
8 = 2 x 4 <--- 2 is a prime number
Reduce 4 to the product of primes:
4 = 2 x 2 <--- 2 is a prime number
Reduce 2 to the product of primes:
2 x 2 x 2
23
1 + 8 + 2 + 4 = 15
This is the sum of all the factors except the number
1 + 2 + 4 = 7