1/2a-10b=c solve for a
Multiply each side of the equation by 2:
2/2a - 2(10)b = 2c
Simplify:
a - 20b = 2c
Add 20b to each side:
a - 20b + 20b = 2c + 20b
Cancel the 20b on the left side:
a = 2c + 20b
You can also factor out a 2 on the left side for another version of this answer:
a = 2(c + 10b)
Solve mgh=1/2mv^2+1/2(2/5)mr^2(v^2/r^2) for v
1/2(2/5) = 1/5 since the 2's cancel
r^2/r^2 = 1
So we simplify, and get:
mgh=1/2mv^2+1/5(mv^2) for v
Divide each side by m, so m's cancel in each term on the left and right side:
gh = 1/2v^2 + 1/5(v^2)
Combine like terms for v^2 on the right...
Consider the formula for the area of a trapezoid: A=12h(a+b) . Is it mathematically simpler to solve for a, b, or h? Why? Solve for each of these variables to demonstrate.
The variable "h" is the easiest to solve for. Because you only have one step. Let's review:
Divide each side of the...
z = (x + y)/mx; Solve for x
Cross multiply:
zmx = x + y
Subtract x from each side
zmx - x = y
Factor out x
x(zm - 1) = y
Divide each side by zm - 1
x = y/(zm - 1)
A=a+b+c+d÷4 for c
Assume A and a are different variables:
Cross multiply:
a + b + c + d = 4A
Subtract a, b, and d from each side:
a + b + c + d - (a + b + d) = 4A - (a + b + d)
Cancel the a + b + d on the left side
c = 4A - a - b - d
Subtract 15 from each side:
5d/11 = P - 15
Multiply each side by 11
5d = 11p - 165
Divide each side of the equation by d:
d = (11p - 165)
------------
5