natural numbers
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A person places $96300 in an investment account earning an annual rate of 2.8%, compounded continuouA person places $96300 in an investment account earning an annual rate of 2.8%, compounded continuously. Using the formula V=PertV = Pe^{rt} V=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 7 years.
Substituting our given numbers in where P = 96,300, r = 0.028, and t = 7, we get:
V = 96,300 * e^(0.028 * 7)
V = 96,300 * e^0.196
V = 96,300 * 1.21652690533
V = [B]$117,151.54[/B]
list the natural numbers less than 70 that are divisible by 8list the natural numbers less than 70 that are divisible by 8
Natural numbers are {1, 2, 3, ...
We want natural numbers less than 70 which are divisible by 8:
[LIST]
[*]8 * 1 = 8
[*]8 * 2 = 16
[*]8 * 3 = 24
[*]8 * 4 = 32
[*]8 * 5 = 40
[*]8 * 6 = 48
[*]8 * 7 = 56
[*]8 * 8 = 64
[/LIST]
Our answer is:
[B]{8, 16, 24, 32, 40, 48, 56, 64}[/B]
Natural Logarithm TableFree Natural Logarithm Table Calculator - Generates a natural logarithm table for the first (n) numbers rounded to (r) digits
Natural NumbersFree Natural Numbers Calculator - Shows a set amount of natural numbers and cumulative sum
natural numbers that are factors of 16natural numbers that are factors of 16
Natural numbers are positive integers starting at 1.
{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16}
Of these, [URL='https://www.mathcelebrity.com/factoriz.php?num=16&pl=Show+Factorization']the only factors of 16[/URL] are:
{[B]1, 2, 4, 8, 16}[/B]
Olga wrote all the natural numbers from 1 to k. Including 1 and k. How many numbers did she write?Olga wrote all the natural numbers from 1 to k. Including 1 and k. How many numbers did she write?
The formula for the number of numbers including A to B is:
B - A + 1
With A = 1 and B = k, we have:
k - 1 + 1
[B]k[/B]
P is the natural numbers that are factors of 25P is the natural numbers that are factors of 25
we type in [I][URL='https://www.mathcelebrity.com/factoriz.php?num=25&pl=Show+Factorization']factor 25[/URL][/I] into our math engine and we get:
{1, 5, 25}
Since [U]all[/U] of these are natural numbers, our answer is:
[B]{1, 5, 25}[/B]
Rational,Irrational,Natural,Integer PropertyFree Rational,Irrational,Natural,Integer Property Calculator - This calculator takes a number, decimal, or square root, and checks to see if it has any of the following properties:
* Integer Numbers
* Natural Numbers
* Rational Numbers
* Irrational Numbers
Handles questions like:
Irrational or rational numbers
Rational or irrational numbers
rational and irrational numbers
Rational number test
Irrational number test
Integer Test
Natural Number Test
Sum of the First (n) NumbersFree Sum of the First (n) Numbers Calculator - Determines the sum of the first (n)
* Whole Numbers
* Natural Numbers
* Even Numbers
* Odd Numbers
* Square Numbers
* Cube Numbers
* Fourth Power Numbers
Suppose x is a natural number. When you divide x by 7 you get a quotient of q and a remainder of 6.Suppose x is a natural number. When you divide x by 7 you get a quotient of q and a remainder of 6. When you divide x by 11 you get the same quotient but a remainder of 2. Find x.
[U]Use the quotient remainder theorem[/U]
A = B * Q + R where 0 ≤ R < B where R is the remainder when you divide A by B
Plugging in our numbers for Equation 1 we have:
[LIST]
[*]A = x
[*]B = 7
[*]Q = q
[*]R = 6
[*]x = 7 * q + 6
[/LIST]
Plugging in our numbers for Equation 2 we have:
[LIST]
[*]A = x
[*]B = 11
[*]Q = q
[*]R = 2
[*]x = 11 * q + 2
[/LIST]
Set both x values equal to each other:
7q + 6 = 11q + 2
Using our [URL='http://www.mathcelebrity.com/1unk.php?num=7q%2B6%3D11q%2B2&pl=Solve']equation calculator[/URL], we get:
q = 1
Plug q = 1 into the first quotient remainder theorem equation, and we get:
x = 7(1) + 6
x = 7 + 6
[B]x = 13[/B]
Plug q = 1 into the second quotient remainder theorem equation, and we get:
x = 11(1) + 2
x = 11 + 2
[B]x = 13[/B]
the set of natural numbers less than 7 that are divisible by 3the set of natural numbers less than 7 that are divisible by 3
Natural Numbers less than 7
{1, 2, 3, 4, 5, 6}
Only 2 of them are divisible by 3. Divisible means the number is divided evenly, with no remainder:
[B]{3, 6}[/B]
the sum of 3 consecutive natural numbers, the first of which is nthe sum of 3 consecutive natural numbers, the first of which is n
Natural numbers are counting numbers, so we the following expression:
n + (n + 1) + (n + 2)
Combine n terms and constants:
(n + n + n) + (1 + 2)
[B]3n + 3
Also expressed as 3(n + 1)[/B]
the sum of 3 consecutive natural numbers, the first of which is nthe sum of 3 consecutive natural numbers, the first of which is n
We have:
n + (n + 1) + (n + 2)
Grouping like terms, we have:
[B]3n + 3[/B]
The sum of 3 consecutive natural numbers, the first of which is nThe sum of 3 consecutive natural numbers, the first of which is n.
We have 3 numbers:
n, n + 1, and n + 2
Add them up:
n + (n + 1) + (n + 2)
Group like terms:
[B]3n + 3[/B]
X is a natural number greater than 6I saw this ticket come through today.
The answer is x > 6.
Natural numbers are positive numbers not 0. So 1, 2, 3, ...
Let me build this shortcut into the calculator.
Also, here is the[URL='http://www.mathcelebrity.com/interval-notation-calculator.php?num=x%3E6&pl=Show+Interval+Notation'] interval notation[/URL] for that expression.