counting - taking account of when reaching a total; including
3 salads, 4 main dishes, and 2 desserts3 salads, 4 main dishes, and 2 desserts
Total meal combinations are found by multiplying each salad, main dish, and dessert using the fundamental rule of counting.
The fundamental rule of counting states, if there are a ways of doing one thing, b ways of doing another thing, and c ways of doing another thing, than the total combinations of all the ways are found by a * b * c.
With 3 salads, 4 main dishes, and 2 desserts, our total meal combinations are:
3 * 4 * 2 = [B]24 different meal combinations.[/B]
5 shirts. 3 pants and 8 shoes how many outfits can you wear5 shirts. 3 pants and 8 shoes how many outfits can you wear
Using the fundamental rule of counting, we can have:
5 shirts * 3 pants * 8 shoes = [B]120 different outfits[/B]
7 salads, 10 main dish, 6 dessert7 salads, 10 main dish, 6 dessert
Using the Fundamental Rule of Counting, we have:
7 * 10 * 6 = 420 possible meals
A numerical pass code is required to open a car door. The pass code is five digits long and uses theA numerical pass code is required to open a car door. The pass code is five digits long and uses the digits 0-9. Numbers may be repeated in the pass code. How many different pass codes exist?
0-9 is 10 digits. Since digits can repeat, we use the fundamental rule of counting to get:
10 * 10 * 10 * 10 * 10 = [B]100,000 different pass codes[/B]
A restaurant offers 20 appetizers and 40 main courses, how many ways can a person order a two courseA restaurant offers 20 appetizers and 40 main courses, how many ways can a person order a two course meal?
Using the fundamental rule of counting, we can have:
20 appetizers * 40 main courses = [B]800 possible two-course meals[/B]
A restaurant offers the following options: Starter – soup or salad Main – chicken, fish or vegetarA restaurant offers the following options:
[LIST]
[*]Starter – soup or salad
[*]Main – chicken, fish or vegetarian
[*]Dessert – ice cream or cake
[/LIST]
How many possible different combinations of starter, main and dessert are there?
Using the fundamental rule of counting, we have:
2 starters * 3 main courses * 2 desserts = [B]12 different combinations
[MEDIA=youtube]-N9j7FQ8Le4[/MEDIA][/B]
A three digit number, if the digits are uniqueA three digit number, if the digits are unique
[LIST=1]
[*]For our first digit, we can start with anything but 0. So we have 9 options
[*]For our second digit, we can use anything but 9 since we want to be unique. So we have 9 options
[*]For our last digit, we can use anything but the first and second digit. So we have 10 - 2 = 8 options
[/LIST]
Our total 3 digit numbers with all digits unique is found by the fundamental rule of counting:
9 * 9 * 8 = [B]648 possible 3 digit numbers[/B]
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Alice is making a sandwich to pack in her lunch. She has 2 different kinds of bread, 3 cheeses, 4 luAlice is making a sandwich to pack in her lunch. She has 2 different kinds of bread, 3 cheeses, 4 lunch meats, and 2 condiments to choose from. Assuming she uses one of each of bread, cheese, meat, and condiment, how many different sandwiches can she make?
We use the Fundamental Rule of Counting
[LIST]
[*]Bread: 2
[*]Cheeses: 3
[*]Lunch Meats: 4
[*]Condiments: 2
[/LIST]
2 * 3 * 4 * 2 = [B]48 different sandwiches[/B]
An ice cream shop carries 6 ice cream flavors, 3 sauces, and 4 toppings. If a sundae has one scoop oAn ice cream shop carries 6 ice cream flavors, 3 sauces, and 4 toppings. If a sundae has one scoop of ice cream, one sauce, and one topping, how many different sundaes can be created?
Using the rule of counting, we have:
We have 6 possible ice cream flavors * 3 possible sauces * 4 possible toppings = [B]72 possible sundaes[/B]
Blackjack Card CountingFree Blackjack Card Counting Calculator - This calculator allows you to enter a number of players with one deck of cards by simulating an opening blackjack deal using card counting methods.
camille has 7 blouses,2 skirts,3 pair of short pants and 5 pair of jeans.how many different outfitscamille has 7 blouses,2 skirts,3 pair of short pants and 5 pair of jeans.how many different outfits can he wear,assuming that he always wear a belt.
Using the fundamental rule of counting, we find total amount of different outfits as follows:
7 blouses * 2 skirts * 3 pair of short pants * 5 pair of jeans = [B]210 outfits[/B].
Change CountingFree Change Counting Calculator - This shows you how to make change using the least amount of bills/coins by taking a bill amount and a cash tendered amount from a customer and figuring out the fastest way to make change. Maximum denomination is $100
Choosing coffee or tea; with cream, milk, or honey; served in a glass or plastic cupChoosing coffee or tea; with cream, milk, or honey; served in a glass or plastic cup
Using the fundamental rule of counting:
2 drink types * 3 sweetness * 2 cups = [B]12 possible choices[/B]
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Find the last digit of 7^2013Consider the first 8 calculations of 7 to an exponent:
[LIST]
[*]7^1 = 7
[*]7^2 = 49
[*]7^3 = 343
[*]7^4 = 2,401
[*]7^5 = 16,807
[*]7^6 = 117,649
[*]7^7 = 823,543
[*]7^8 = 5,764,801
[/LIST]
Take a look at the last digit of the first 8 calculations:
7, 9, 3, 1, 7, 9, 3, 1
The 7, 9, 3, 1 repeats through infinity.
So every factor of 4, the cycle of 7, 9, 3, 1 restarts.
Counting backwards from 2013, we know that 2012 is the largest number divisible by 4:
7^2013 = 7^2012 * 7^1
The cycle starts over after 2012.
Which means the last digit of 7^2013 = [B]7
[MEDIA=youtube]Z157jj8R7Yc[/MEDIA][/B]
Fundamental Rule of CountingFree Fundamental Rule of Counting Calculator - Given a set of items, this calculates the total number of groups/choices that can be formed using the rule of product.
if joey has 5 swimsuits, 3 bicycles, and 4 pairs of running shoes, how many ways are there for joeyif joey has 5 swimsuits, 3 bicycles, and 4 pairs of running shoes, how many ways are there for joey to choose
Using the Fundamental Rule of Counting, we have:
5 swimsuits * 3 bicycles * 4 pairs of running shoes = [B]60 possible choices[/B]
if you own 5 pants, 8 shirts, and 3 jackets how many outfits can you make wearing 1 of each itemif you own 5 pants, 8 shirts, and 3 jackets how many outfits can you make wearing 1 of each item?
Using the Fundamental Rule of counting, we have:
Total Pants * Total Shirts * Total Jackets
5 * 8 * 3
[B]120 [/B]
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License plate that is made up of 4 letters followed by 2 numbersLicense plate that is made up of 4 letters followed by 2 numbers
Using the fundamental rule of counting, we have:
26 possible letters * 26 possible letters * 26 possible letters * 26 possible letters * 10 possible numbers * 10 possible numbers = [B]45,697,600 license plate combinations[/B]
License plates are made using 3 letters followed by 2 digits. How many plates can be made if repetitLicense plates are made using 3 letters followed by 2 digits. How many plates can be made if repetition of letters and digits is allowed
We have 26 letters A-Z and 10 possible digits 0-9. Using the fundamental rule of counting, we have:
26 * 26 * 26 * 10 * 10 = [B]1,757,600 possible choices[/B]
License plates are made using 3 letters followed by 3 digits. How many plates can be made of repetitLicense plates are made using 3 letters followed by 3 digits. How many plates can be made of repetition of letters and digits is allowed
We have 26 letters in the alphabet
We have 10 digits [0-9]
The problem asks for the following license plate scenario of Letters (L) and Digits (D)
LLLDDD
The number of plates we can make using L = 26 and D = 10 using the fundamental rule of counting is:
Number of License Plates = 26 * 26 * 26 * 10 * 10 * 10
Number of License Plates = [B]17,576,000[/B]
Lisa has 5 skirts, 10 blouses, and 4 jackets. How many 3-piece outfits can she put together assumingLisa has 5 skirts, 10 blouses, and 4 jackets. How many 3-piece outfits can she put together assuming any piece goes with any other?
Using the fundamental rule of counting, we have:
5 * 10 * 4 = [B]200 different 3-piece outfits[/B]
the sum of 3 consecutive natural numbers, the first of which is nthe sum of 3 consecutive natural numbers, the first of which is n
Natural numbers are counting numbers, so we the following expression:
n + (n + 1) + (n + 2)
Combine n terms and constants:
(n + n + n) + (1 + 2)
[B]3n + 3
Also expressed as 3(n + 1)[/B]