What is the sum of four consecutive multiples of 5?
First number = n
Second number = n + 5
Third number = n + 10
Fourth number = n + 15
Add them together:
(n + n + n + n) + (5 + 10 + 15)
4n + 30
First number = n
Second number = n + 5
Third number = n + 10
Fourth number = n + 15
Add them together:
(n + n + n + n) + (5 + 10 + 15)
4n + 30