We can't add a common number of multiply a common number to solve this.
But what happens if we start at the 3rd term and add the 2 prior terms?
But what happens if we start at the 3rd term and add the 2 prior terms?
- 0 + 1= 1
- 1 + 1 = 2
- 1 + 2 = 3
- 3 + 5 = 8
- 5 + 8 = 13
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