two numbers have an average of 2100 and one number is $425 more than the other number. What are the

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two numbers have an average of 2100 and one number is $425 more than the other number. What are the numbers

Let the first number be x and the second number be y. We're given two equations:

1. (x + y)/2 = 2100 (Average)
2. y = x + 425

Rearrange equation (1) by cross multiplying
x + y = 2 * 2100
x + y = 4200

So we have our revised set of equations:

1. x + y = 4200
   
2. y = x + 425

Substituting equation (2) into equation (1) for y, we get:
x + (x + 425) = 4200

Combining like terms, we get:
2x + 425 = 4200

Using our equation solver, we get:
x = 1887.5

Which means using equation (2), we get
y = 1887.5 + 425
y = 2312.5