The length of a rectangle is three times its width.If the perimeter is 80 feet, what are the dimensions?
We're given 2 equations:
2(3w) + 2w = 80
6w + 2w = 80
8w = 80
Divide each side by 8:
8w/8 = 80/8
w = 10
Substitute w = 10 into (1)
l = 3(10)
l = 30
We're given 2 equations:
- l = 3w
- P = 80 = 2l + 2w = 80
2(3w) + 2w = 80
6w + 2w = 80
8w = 80
Divide each side by 8:
8w/8 = 80/8
w = 10
Substitute w = 10 into (1)
l = 3(10)
l = 30