The difference between two positive numbers is 5 and the square of their sum is 169.
Let the two positive numbers be a and b. We have the following equations:
(b + 5 + b)^2 = 169
(2b + 5)^2 = 169
Run (2b + 5)^2 through our search engine, and you get:
4b^2 + 20b + 25
Set this equal to 169 above:
4b^2 + 20b + 25 = 169
Run that quadratic equation in our search engine, and you get:
b = (-9, 4)
But the problem asks for positive numbers. So b = 4 is one of our solutions.
Substitute b = 4 into equation (1) above, and we get:
a - b = 5
a - 4 = 5
a = 9
Therefore, we have (a, b) = (9, 4)
Let the two positive numbers be a and b. We have the following equations:
- a - b = 5
- (a + b)^2 = 169
- Rearrange (1) by adding b to each side. We have a = b + 5
(b + 5 + b)^2 = 169
(2b + 5)^2 = 169
Run (2b + 5)^2 through our search engine, and you get:
4b^2 + 20b + 25
Set this equal to 169 above:
4b^2 + 20b + 25 = 169
Run that quadratic equation in our search engine, and you get:
b = (-9, 4)
But the problem asks for positive numbers. So b = 4 is one of our solutions.
Substitute b = 4 into equation (1) above, and we get:
a - b = 5
a - 4 = 5
a = 9
Therefore, we have (a, b) = (9, 4)