Sara has a box of candies. In the box there are 8 pink candies, 7 purple candies and 5 blue candies. She takes one candy and records its color. She then puts it back in the box and draws another candy. What is the probability of taking out a pink candy followed by a blue candy?
Calculate the total number of candies:
Total candies = Pink + Purple + Blue
Total candies = 8 + 7 + 5
Total candies = 20
Calculate the probability of drawing one pink candy:
P(Pink) = 8/20
Using our fraction reduction calculator, we get:
P(Pink) = 2/5
Calculate the probability of drawing one blue candy:
P(Blue) = 5/20 <-- 20 options since Sara replaced her first draw
Using our fraction reduction calculator, we get:
P(Blue) = 1/4
The problem asks for the probability of a Pink followed by a Blue. Since each event is independent, we multiply:
P(Pink, Blue) = P(Pink) * P(Blue)
P(Pink, Blue) = 2/5 * 1/4
P(Pink, Blue) = 2/20
Using our fraction reduction calculator, we get:
P(Pink, Blue) = 1/10 or 10%
Calculate the total number of candies:
Total candies = Pink + Purple + Blue
Total candies = 8 + 7 + 5
Total candies = 20
Calculate the probability of drawing one pink candy:
P(Pink) = 8/20
Using our fraction reduction calculator, we get:
P(Pink) = 2/5
Calculate the probability of drawing one blue candy:
P(Blue) = 5/20 <-- 20 options since Sara replaced her first draw
Using our fraction reduction calculator, we get:
P(Blue) = 1/4
The problem asks for the probability of a Pink followed by a Blue. Since each event is independent, we multiply:
P(Pink, Blue) = P(Pink) * P(Blue)
P(Pink, Blue) = 2/5 * 1/4
P(Pink, Blue) = 2/20
Using our fraction reduction calculator, we get:
P(Pink, Blue) = 1/10 or 10%