Refer to a bag containing 13 red balls numbered 1-13 and 5 green balls numbered 14-18. You choose a

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Refer to a bag containing 13 red balls numbered 1-13 and 5 green balls numbered 14-18. You choose a ball at random.

a. What is the probability that you choose a red or even numbered ball?

b. What is the probability you choose a green ball or a ball numbered less than 5?

a. The phrase or in probability means add. But we need to subtract even reds so we don't double count:
We have 18 total balls, so this is our denonminator for our fractions.
Red and Even balls are {2, 4, 6, 8, 10, 12}

Our probability is:
P(Red or Even) = P(Red) + P(Even) - P(Red and Even)
P(Red or Even) = 13/18 + 9/18 - 6/18
P(Red or Even) = 16/18

Using our Fraction Simplify Calculator, we have:
P(Red or Even) = 16/18

b. The phrase or in probability means add. But we need to subtract greens less than 5 so we don't double count:
We have 18 total balls, so this is our denonminator for our fractions.
Green and less than 5 does not exist, so we have no intersection

Our probability is:
P(Green or Less Than 5) = P(Green) + P(Less Than 5) - P(Green And Less Than 5)
P(Green or Less Than 5) = 5/18 + 4/18 - 0
P(Green or Less Than 5) = 9/18

Using our Fraction Simplify Calculator, we have:
P(Red or Even) = 1/2