One number is 8 times another number. The numbers are both positive and have a difference of 70.
Let the first number be x, the second number be y. We're given:
8y - y = 70
Plugging this equation into our search engine, we get:
y = 10 <-- This is the smaller number
Plug this into Equation (1), we get:
x = 8(10)
x = 80 <-- This is the larger number
Let the first number be x, the second number be y. We're given:
- x = 8y
- x - y = 70
8y - y = 70
Plugging this equation into our search engine, we get:
y = 10 <-- This is the smaller number
Plug this into Equation (1), we get:
x = 8(10)
x = 80 <-- This is the larger number