one number is 3 times as large as another. Their sum is 48. Find the numbers
Let the first number be x. Let the second number be y. We're given two equations:
3y + y = 48
To solve for y, we type this equation into the search engine and we get:
y = 12
Now, plug y = 12 into equation (1) to solve for x:
x = 3(12)
x = 36
Let the first number be x. Let the second number be y. We're given two equations:
- x = 3y
- x + y = 48
3y + y = 48
To solve for y, we type this equation into the search engine and we get:
y = 12
Now, plug y = 12 into equation (1) to solve for x:
x = 3(12)
x = 36