larger of 2 numbers is 12 more than the smaller number. if the sum of the 2 numbers is 74 find the 2 numbers
Declare Variables for each number:
s + 12 + s = 74
Solve for s in the equation s + 12 + s = 74
Step 1: Group the s terms on the left hand side:
(1 + 1)s = 2s
Step 2: Form modified equation
2s + 12 = + 74
Step 3: Group constants:
We need to group our constants 12 and 74. To do that, we subtract 12 from both sides
2s + 12 - 12 = 74 - 12
Step 4: Cancel 12 on the left side:
2s = 62
Step 5: Divide each side of the equation by 2
2s/2 = 62/2
s = 31
To solve for l, we substitute in s = 31 into equation (1):
l = 31 + 12
l = 43
Declare Variables for each number:
- Let l be the larger number
- Let s be the smaller number
- l = s + 12
- l + s = 74
s + 12 + s = 74
Solve for s in the equation s + 12 + s = 74
Step 1: Group the s terms on the left hand side:
(1 + 1)s = 2s
Step 2: Form modified equation
2s + 12 = + 74
Step 3: Group constants:
We need to group our constants 12 and 74. To do that, we subtract 12 from both sides
2s + 12 - 12 = 74 - 12
Step 4: Cancel 12 on the left side:
2s = 62
Step 5: Divide each side of the equation by 2
2s/2 = 62/2
s = 31
To solve for l, we substitute in s = 31 into equation (1):
l = 31 + 12
l = 43