math_celebrity Administrator Staff member Feb 11, 2023 #1 Jay has 5 paintings that he plans to display on a wall that only has 4 books. Nancy has 5 paintings that she plans to display on a wall with 5 hooks. Who has more possible ways to hang his/her paintings? Jay's ways: 5 P 4 = 120 Nancy's ways: 5 P 5 = 120 Therefore, they have the same number of ways.
Jay has 5 paintings that he plans to display on a wall that only has 4 books. Nancy has 5 paintings that she plans to display on a wall with 5 hooks. Who has more possible ways to hang his/her paintings? Jay's ways: 5 P 4 = 120 Nancy's ways: 5 P 5 = 120 Therefore, they have the same number of ways.
