If the third of 6 consecutive numbers is 12, what is their sum?

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If the third of 6 consecutive numbers is 12, what is their sum?


If 12 is the third of 6 consecutive numbers:
First consecutive number is 12 - 2 = 10
Second consecutive number = 12 - 1 = 11
Third consecutive number = 12
Fourth consecutive number = 12 + 1 = 13
Fifth consecutive number = 13 + 1 = 14
Sixth consecutive number = 14 + 1 = 15

The sum of all consecutive numbers is:
10 + 11 + 12 + 13 + 14 + 15 = 75