Given: BC = EF AC = EG AB = 10 BC = 3 Prove FG = 10 | MathCelebrity Forum

Given: BC = EF AC = EG AB = 10 BC = 3 Prove FG = 10

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Given: BC = EF

AC = EG

AB = 10

BC = 3

Prove FG = 10

  • AC = AB + BC (Segment Addition Postulate)
  • AB = 10, BC = 3 (Given)
  • AC = 10 + 3 (Substitution Property of Equality)
  • AC = 13 (Simplify)
  • AC = EG, BC = EF (Given)
  • EG = 13, EF = 3 (Segment Equivalence)
  • EG = EF + FG (Segment Addition Postulate)
  • 13 = 3 + FG (Substitution Property of Equality)
  • FG = 10 (Subtraction Property)
 
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