From a group of 10 men and 8 women, how many ways can 2 men and 3 women be chosen for 5 positions

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From a group of 10 men and 8 women, how many ways can 2 men and 3 women be chosen for 5 positions?

We use combinations. Since men and women are independent, we multiply each result:
We want 10 men choose 2 men multiplied by 8 women choose 3 women.
Type 10C2 into our search engine and we get 45
Type 8C3 into our search engine and we get 56

Multiply both together:
45 * 56 = 2,520 ways