Find 3 Even Integers with a sum of 198
Let x be the first even integer. Then y is the next, and z is the third even integer.
x + x + 2 + x + 4 = 198
Group x terms
3x + 6 = 198
Using our equation solver, we get:
x = 64
y = 64 + 2
y= 66
z = 64 + 4
z = 68
Let x be the first even integer. Then y is the next, and z is the third even integer.
- y = x + 2
- z = x + 4
- x + y + z = 198
x + x + 2 + x + 4 = 198
Group x terms
3x + 6 = 198
Using our equation solver, we get:
x = 64
y = 64 + 2
y= 66
z = 64 + 4
z = 68