Find 2 consecutive numbers such that the sum of twice the smaller number and 3 times the larger number is 73.
Let x be the smaller number and y be the larger number. We are given:
2x + 3y = 73
Since the numbers are consecutive, we know that y = x + 1. Substitute this into our given equation:
2x + 3(x + 1) = 73
Multiply through:
2x + 3x + 3 = 73
Group like terms:
5x + 3 = 73
Type 5x + 3 = 73 into the search engine, and we get x = 14.
Our larger number is 14 + 1 = 15
Therefore, our consecutive numbers are (14, 15)
Let x be the smaller number and y be the larger number. We are given:
2x + 3y = 73
Since the numbers are consecutive, we know that y = x + 1. Substitute this into our given equation:
2x + 3(x + 1) = 73
Multiply through:
2x + 3x + 3 = 73
Group like terms:
5x + 3 = 73
Type 5x + 3 = 73 into the search engine, and we get x = 14.
Our larger number is 14 + 1 = 15
Therefore, our consecutive numbers are (14, 15)