Dan's school is planning a field trip to an art museum. Bus company A charges a $60 rental fee plus $4 per student. Bus company B charges $150 plus $2 per student. How many students would have to go for the cost to be the same?
Set up Company A's cost equation C(s) where s is the number of students
C(s) = Cost per student * s + Rental Fee
C(s) = 4s + 60
Set up Company B's cost equation C(s) where s is the number of students
C(s) = Cost per student * s + Rental Fee
C(s) = 2s + 150
The problem asks for s where both C(s) equations would be equal. So we set Company A and Company B's C(s) equal to each other:
4s + 60 = 2s + 150
To solve for s, we type this equation into our search engine and we get:
s = 45
Set up Company A's cost equation C(s) where s is the number of students
C(s) = Cost per student * s + Rental Fee
C(s) = 4s + 60
Set up Company B's cost equation C(s) where s is the number of students
C(s) = Cost per student * s + Rental Fee
C(s) = 2s + 150
The problem asks for s where both C(s) equations would be equal. So we set Company A and Company B's C(s) equal to each other:
4s + 60 = 2s + 150
To solve for s, we type this equation into our search engine and we get:
s = 45