Customers arrive at the claims counter at the rate of 20 per hour (Poisson distributed). What is the probability that the arrival time between consecutive customers is less than five minutes?
Use the exponential distribution
20 per 60 minutes is 1 every 3 minutes
1/λ = 3 so λ = 0.333333333
Using the exponential distribution calculator, we get F(5,0.333333333) = 0.811124396848
Use the exponential distribution
20 per 60 minutes is 1 every 3 minutes
1/λ = 3 so λ = 0.333333333
Using the exponential distribution calculator, we get F(5,0.333333333) = 0.811124396848