cscx-cotx*cosx=sinx

[math_celebrity]

cscx-cotx*cosx=sinx

A few transformations we can make based on trig identities:

• csc(x) = 1/sin(x)
• cot(x) = cos(x)/sin(x)

So we have:
1/sin(x) - cos(x)/sin(x) * cos(x) = sin(x)
(1 - cos^2(x))/sin(x) = sin(x)

1 - cos^2(x) = sin^2(x)

This is true from the identity:
sin^2(x) - cos^2(x) = 1