Company a charges $25 plus $0.10 a mile. Company b charges $20 plus $0.15 per mile. How far would yo | MathCelebrity Forum

Company a charges $25 plus $0.10 a mile. Company b charges $20 plus $0.15 per mile. How far would yo

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Company a charges $25 plus $0.10 a mile. Company b charges $20 plus $0.15 per mile. How far would you need to travel to get each charge to be the same?

Let x be the number of miles traveled
Company A charge: C = 25 + 0.10x
Company B charge: C = 20 + 0.15x

Set up an equation find out when the charges are the same.
25 + 0.10x = 20 + 0.15x

Combine terms and simplify
0.05x = 5

Divide each side of the equation by 0.05 to isolate x
x = 100
 
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