can you continue this pattern 1,5,13,29
Looking at the numbers, we see a pattern of the next number as the prior number * 2 and then add 3
With each term as t(n), we find t(n + 1) as:
t(n + 1) = 2*t(n) + 3
t(2) = 2(1) + 3 = 2 + 3 = 5
t(3) = 2(5) + 3 = 10 + 3 = 13
t(4) = 2(13) + 3 = 26 + 3 = 29
t(5) = 2(29) + 3 = 58 + 3 = 61
Looking at the numbers, we see a pattern of the next number as the prior number * 2 and then add 3
With each term as t(n), we find t(n + 1) as:
t(n + 1) = 2*t(n) + 3
t(2) = 2(1) + 3 = 2 + 3 = 5
t(3) = 2(5) + 3 = 10 + 3 = 13
t(4) = 2(13) + 3 = 26 + 3 = 29
t(5) = 2(29) + 3 = 58 + 3 = 61