by + 2/3 = c for y | MathCelebrity Forum

by + 2/3 = c for y

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by + 2/3 = c for y

Subtract 2/3 from each side of the literal equation:
by + 2/3 - 2/3 = c - 2/3

Cancel the 2/3 on the left side to get:
by = c - 2/3

Divide each side by b to isolate y:
by/b = (c - 2/3)/b

Cancel the b's on the left side to get:
y = (c - 2/3)/b
 
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