Below are data showing the results of six subjects on a memory test. The three scores per subject are their scores on three trials (a, b, and c) of a memory task. Are the subjects getting better each trial? Test the linear effect of trial for the data.
A score trial B score trial 2 C Score trial 3
4 6 7
3 7 8
2 8 5
1 4 7
4 6 9
2 4 2
(a) Compute L for each subject using the contrast weights -1, 0, and 1. That is, compute (-1)(a) + (0)(b) + (1)(c) for each subject.
(b) Compute a one-sample t-test on this column (with the L values for each subject) you created. Formula t = To computer a one-sample t-test first know the meaning of each letter
(a) Each L column value is just -1(Column 1) + 0(Column2) + 1(Column 3)
A score trial B score trial 2 C Score trial 3 L = (-1)(a) + (0)(b) + (1)(c)
4 6 7 3
3 7 8 5
2 8 5 3
1 4 7 6
4 6 9 5
2 4 2 0
(b) Mean = (3 + 5 + 3 + 6 + 5 + 0)/6 = 22/6 = 3.666666667
Standard Deviation = 2.160246899
Use 3 as our test mean
(3.666667 - 3)/(2.160246899/sqrt(6)) = 0.755928946
A score trial B score trial 2 C Score trial 3
4 6 7
3 7 8
2 8 5
1 4 7
4 6 9
2 4 2
(a) Compute L for each subject using the contrast weights -1, 0, and 1. That is, compute (-1)(a) + (0)(b) + (1)(c) for each subject.
(b) Compute a one-sample t-test on this column (with the L values for each subject) you created. Formula t = To computer a one-sample t-test first know the meaning of each letter
(a) Each L column value is just -1(Column 1) + 0(Column2) + 1(Column 3)
A score trial B score trial 2 C Score trial 3 L = (-1)(a) + (0)(b) + (1)(c)
4 6 7 3
3 7 8 5
2 8 5 3
1 4 7 6
4 6 9 5
2 4 2 0
(b) Mean = (3 + 5 + 3 + 6 + 5 + 0)/6 = 22/6 = 3.666666667
Standard Deviation = 2.160246899
Use 3 as our test mean
(3.666667 - 3)/(2.160246899/sqrt(6)) = 0.755928946