A spinner has 3 equal sections labelled A, B, C. A bag contains 3 marbles: 1 grey, 1 black, and 1 white. The pointer is spun and a marble is picked at random.
a) Use a tree diagram to list the possible outcomes.
i) spinning A?
P(A) = Number of A sections on spinner / Total Sections
P(A) = 1/3
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ii) picking a grey marble?
P(A) = Number of grey marbles / Total Marbles
P(A) = 1/3
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iii) spinning A and picking a white marble?
Since they're independent events, we multiply to get:
P(A AND White) = P(A) * P(White)
P(A) was found in i) as 1/3
Find P(White):
P(White) = Number of white marbles / Total Marbles
P(White) = 1/3
Therefore, we have:
P(A AND White) = 1/3 * 1/3
P(A AND White) = 1/9
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iv) spinning C and picking a pink marble?
Since they're independent events, we multiply to get:
P(C AND Pink) = P(C) * P(Pink)
Find P(C):
P(C) = Number of C sections on spinner / Total Sections
P(C) = 1/3
Find P(Pink):
P(Pink) = Number of pink marbles / Total Marbles
P(Pink) = 0/3
Therefore, we have:
P(C AND Pink) = 1/3 * 0
P(C AND Pink) = 0
a) Use a tree diagram to list the possible outcomes.
- A, Grey
- A, Black
- A, White
- B, Grey
- B, Black
- B, White
- C, Grey
- C, Black
- C, White
i) spinning A?
P(A) = Number of A sections on spinner / Total Sections
P(A) = 1/3
---------------------------------
ii) picking a grey marble?
P(A) = Number of grey marbles / Total Marbles
P(A) = 1/3
---------------------------------
iii) spinning A and picking a white marble?
Since they're independent events, we multiply to get:
P(A AND White) = P(A) * P(White)
P(A) was found in i) as 1/3
Find P(White):
P(White) = Number of white marbles / Total Marbles
P(White) = 1/3
Therefore, we have:
P(A AND White) = 1/3 * 1/3
P(A AND White) = 1/9
---------------------------------
iv) spinning C and picking a pink marble?
Since they're independent events, we multiply to get:
P(C AND Pink) = P(C) * P(Pink)
Find P(C):
P(C) = Number of C sections on spinner / Total Sections
P(C) = 1/3
Find P(Pink):
P(Pink) = Number of pink marbles / Total Marbles
P(Pink) = 0/3
Therefore, we have:
P(C AND Pink) = 1/3 * 0
P(C AND Pink) = 0