A spinner has 10 equally sized sections, 2 are gray 8 are blue. The spinner is spun twice. What is the probability that the first spin lands on blue and the second lands on gray?
P(blue) = Blue sections / Total Sections
P(blue) = 8/10
Reducing this using our simplified fraction calculator, we get:
P(blue) = 4/5
P(gray) = Gray sections / Total Sections
P(blue) = 2/10
Reducing this using our simplified fraction calculator, we get:
P(gray) = 1/5
We want the probability of blue,gray. Since each spin is independent, we multiply the two probabilities to get our answer:
P(blue, gray) = P(blue) * P(gray)
P(blue, gray) = 4/5 * 1/5
P(blue, gray) = 4/25
P(blue) = Blue sections / Total Sections
P(blue) = 8/10
Reducing this using our simplified fraction calculator, we get:
P(blue) = 4/5
P(gray) = Gray sections / Total Sections
P(blue) = 2/10
Reducing this using our simplified fraction calculator, we get:
P(gray) = 1/5
We want the probability of blue,gray. Since each spin is independent, we multiply the two probabilities to get our answer:
P(blue, gray) = P(blue) * P(gray)
P(blue, gray) = 4/5 * 1/5
P(blue, gray) = 4/25