A rectangular room is 3 times as long as it is wide, and its perimeter is 56 meters
Given l = length and w = width, The perimeter of a rectangle is 2l + 2w, we have:
2(3w) + 2w = 56
6w + 2w = 56
To solve this equation for w, we type it in our math engine and we get:
w = 7
To solve for l, we substitute w = 7 into equation (1):
l = 3(7)
l = 21
Given l = length and w = width, The perimeter of a rectangle is 2l + 2w, we have:
- l = 3w
- 2l + 2w = 56
2(3w) + 2w = 56
6w + 2w = 56
To solve this equation for w, we type it in our math engine and we get:
w = 7
To solve for l, we substitute w = 7 into equation (1):
l = 3(7)
l = 21