A rectangular room is 3 times as long as it is wide, and its perimeter is 56 meters. Find the dimensions of the room.
We're given two items:
2l + 2w = P
We plug in the given values l = 3w and P = 56 to get:
2(3w) + 2w = 56
6w + 2w = 56
To solve for w, we plug this equation into our search engine and we get:
w = 7
To solve for l, we plug in w = 7 that we just found into the given equation l = 3w:
l = 3(7)
l = 21
So our dimensions length (l) and width (w) are:
(l, w) = (21, 7)
We're given two items:
- l = 3w
- P = 56
2l + 2w = P
We plug in the given values l = 3w and P = 56 to get:
2(3w) + 2w = 56
6w + 2w = 56
To solve for w, we plug this equation into our search engine and we get:
w = 7
To solve for l, we plug in w = 7 that we just found into the given equation l = 3w:
l = 3(7)
l = 21
So our dimensions length (l) and width (w) are:
(l, w) = (21, 7)