A rectangular house is 68 yards wide and 112 yards long. What is its perimeter?
The perimeter of a rectangle is:
P = 2l + 2w
Plugging in our length of 112 and our width of 68, we get:
P = 2(112) + 2(68)
P = 224 + 136
P = 360
The perimeter of a rectangle is:
P = 2l + 2w
Plugging in our length of 112 and our width of 68, we get:
P = 2(112) + 2(68)
P = 224 + 136
P = 360