A Petri dish contains 2000. The number of bacteria triples every 6 hours. How many bacteria will exist after 3 days?
Determine the amount of tripling periods:
B(t) = 2000 * 3^t
with t = 12 tripling periods, we have:
B(12) = 2000 * 3^12
B(12) = 2000 * 531441
B(12) = 1,062,882,000
Determine the amount of tripling periods:
- There are 24 hours in a day.
- 24 hours in a day * 3 days = 72 hours
- 72 hours / 6 hours tripling period = 12 tripling periods
B(t) = 2000 * 3^t
with t = 12 tripling periods, we have:
B(12) = 2000 * 3^12
B(12) = 2000 * 531441
B(12) = 1,062,882,000