A passenger train left station A at 6:00 P.M. Moving with the average speed 45 mph, it arrived at st | MathCelebrity Forum

A passenger train left station A at 6:00 P.M. Moving with the average speed 45 mph, it arrived at st

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A passenger train left station A at 6:00 P.M. Moving with the average speed 45 mph, it arrived at station B at 10:00 p.m. A transit train left from station A 1 hour later than the passenger train, but it arrived at the station B at the same time with the passenger train. What was the average speed of the transit train?

Passenger Train
  • 45 miles per hour and it got there in 4 hours.
Using our formula D = rt where:
  • D = Distance
  • r = rate
  • t = time
  • D = rt
  • D = 45(4)
  • D = 180 miles from Station A to Station B
Transit Train
  • It has to go the same distance, 180 miles, so D = 180
  • It made it there in 3 hours. This is r
  • We want to solve for t
D = rt
180 = 3r

Divide each side by 3
r = 60 miles per hour
 
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