A committee of 6 students are being selected from a class of 10 girls and 8 boys. How many committees are possible if three must be girls and 3 must be boys?
We want combinations. How many ways can we choose 3 boys from 8 boys:
8 choose 3 = 56
We want combinations. How many ways can we choose 3 girls from 10 girls:
10 choose 3 = 120
Our total choices are found by multiplying each event:
Total committees = (8 boys choose 3) * (10 girls choose 3)
Total committees = 56 * 120
Total committees = 6,720
We want combinations. How many ways can we choose 3 boys from 8 boys:
8 choose 3 = 56
We want combinations. How many ways can we choose 3 girls from 10 girls:
10 choose 3 = 120
Our total choices are found by multiplying each event:
Total committees = (8 boys choose 3) * (10 girls choose 3)
Total committees = 56 * 120
Total committees = 6,720