A circle has a center at (6, 2) and passes through (9, 6) | MathCelebrity Forum

A circle has a center at (6, 2) and passes through (9, 6)

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A circle has a center at (6, 2) and passes through (9, 6)

The radius (r) is found by using the distance formula to get:
r = 5

And the equation of the circle is found by using the center (h, k) and radius r as:
(x - h)^2 + (y - k)^2 = r^2
(x - 6)^2 + (y - 2)^2 = 5^2
(x - 6)^2 + (y - 2)^2 = 25
 
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