A car’s purchase price is $24,000. At the end of each year, the value of the car is three-quarters of the value at the beginning of the year. Write the first four terms of the sequence of the car’s value at the end of each year.
three-quarters means 3/4 or 0.75. So we have the following function P(y) where y is the number of years since purchase price:
P(y) = 24000 * 0.75^y
First four terms:
P(1) = 24000 * 0.75 = 18000
P(2) = 18000 * 0.75 = 13500
P(3) = 13500 * 0.75 = 10125
P(4) = 10125 * 0.75 = 7593.75
three-quarters means 3/4 or 0.75. So we have the following function P(y) where y is the number of years since purchase price:
P(y) = 24000 * 0.75^y
First four terms:
P(1) = 24000 * 0.75 = 18000
P(2) = 18000 * 0.75 = 13500
P(3) = 13500 * 0.75 = 10125
P(4) = 10125 * 0.75 = 7593.75