A cable company charges $75 for installation plus $20 per month. Another cable company offers free installation but charges $35 per month. For how many months of cable service would the total cost from either company be the same
Set ups the cost function for the first cable company C(m) where m is the number of months:
C(m) = cost per month * m + installation fee
C(m) = 20m + 75
Set ups the cost function for the second cable company C(m) where m is the number of months:
C(m) = cost per month * m + installation fee
C(m) = 35m
The problem asks for m when both C(m) functions are equal. So we set both C(m) functions equal and solve for m:
20m + 75 = 35m
To solve for m, we type this equation into our search engine and we get:
m = 5
Set ups the cost function for the first cable company C(m) where m is the number of months:
C(m) = cost per month * m + installation fee
C(m) = 20m + 75
Set ups the cost function for the second cable company C(m) where m is the number of months:
C(m) = cost per month * m + installation fee
C(m) = 35m
The problem asks for m when both C(m) functions are equal. So we set both C(m) functions equal and solve for m:
20m + 75 = 35m
To solve for m, we type this equation into our search engine and we get:
m = 5