a baseball park charges $4.50 per admission ticket. the park has already sold 42 tickets. how many m | MathCelebrity Forum

a baseball park charges $4.50 per admission ticket. the park has already sold 42 tickets. how many m

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a baseball park charges $4.50 per admission ticket. the park has already sold 42 tickets. how many more tickets would they need to sell to earn at least $441?

Let the number of tickets above 42 be t.

A few things to note on this question:
  • The phrase at least means greater than or equal to, so we have an inequality.
  • Earnings = Price * Quantity

We're given:
Earnings = 4.50 * 42 + 4.5t >= 441
Earnings = 189 + 4.5t >= 441

We want to solve this inequality for t:

Solve for t in the inequality 189 + 4.5t ≥ 441

Step 1: Group constants:
We need to group our constants 189 and 441. To do that, we subtract 189 from both sides
4.5t + 189 - 189 ≥ 441 - 189

Step 2: Cancel 189 on the left side:
4.5t ≥ 252

Step 3: Divide each side of the inequality by 4.5
4.5t/4.5 ≥ 252.4.5
t ≥ 56
 
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