A bag contains 6 red balls and 7 green balls. You plan to select 4 balls at random. Determine the probability of selecting 4 green balls.
Assuming draw without replacement of the balls, we have:
P(GGGG) = 7/13 * 6/12 * 5/11 * 4/10
P(GGGG) = 840/17,160
P(GGGG) = 0.05
Assuming draw without replacement of the balls, we have:
- Selection 1: 7 green out of 13 balls
- Selection 2: 6 green out of 12 balls
- Selection 3: 5 green out of 11 balls
- Selection 4: 4 green out of 10 balls
P(GGGG) = 7/13 * 6/12 * 5/11 * 4/10
P(GGGG) = 840/17,160
P(GGGG) = 0.05