A Aniketh Sudunagunta New Member Feb 26, 2017 #1 charlie leaves home going 40 miles per hour. When charlie is 9 miles from home, Danny starts after charlie from the same place, going 55 miles per hour. How long does it take Danny to catch up charlie?
charlie leaves home going 40 miles per hour. When charlie is 9 miles from home, Danny starts after charlie from the same place, going 55 miles per hour. How long does it take Danny to catch up charlie?
math_celebrity Administrator Staff member Feb 26, 2017 #2 Let h be the number of hours that pass when Charlie starts. We have the following equations: Charlie: D = 40h + 9 Danny: D = 55h Set them equal to each other: 40h + 9 = 55h Subtract 40h from both sides: 15h = 9 h = 3/5 3/5 of an hour = 3(60)/5 = 36 minutes
Let h be the number of hours that pass when Charlie starts. We have the following equations: Charlie: D = 40h + 9 Danny: D = 55h Set them equal to each other: 40h + 9 = 55h Subtract 40h from both sides: 15h = 9 h = 3/5 3/5 of an hour = 3(60)/5 = 36 minutes
A Aniketh Sudunagunta New Member Feb 26, 2017 #3 Thank you so much math_celebrity said: Let h be the number of hours that pass when Charlie starts. We have the following equations: Charlie: D = 40h + 9 Danny: D = 55h Set them equal to each other: 40h + 9 = 55h Subtract 40h from both sides: 15h = 9 h = 3/5 3/5 of an hour = 3(60)/5 = 36 minutes Click to expand...
Thank you so much math_celebrity said: Let h be the number of hours that pass when Charlie starts. We have the following equations: Charlie: D = 40h + 9 Danny: D = 55h Set them equal to each other: 40h + 9 = 55h Subtract 40h from both sides: 15h = 9 h = 3/5 3/5 of an hour = 3(60)/5 = 36 minutes Click to expand...