52% of a town's households have children and 25% have pets. If 12% have both, what percent have neit

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52% of a town's households have children and 25% have pets. If 12% have both, what percent have neither

Let C represent households with children. Let P represents households with pets. We have the formula to determine households with Children or Pets as C U P (C Union P) or (C or P):
C U P = C + P - (C and P)
C U P = 52% + 25% - 12%
C U P = 65%

Now, if we want to find what percent have neither, we use (C U P)':
(C U P)' = 100% - (C U P)
(C U P)' = 100% - 65%
(C U P)' = 35%