4 consecutive integers such that the sum of the first 3 integers is equal to the 4th

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4 consecutive integers such that the sum of the first 3 integers is equal to the 4th

Let n be our first consecutive integer.

1. n
2. n + 1
3. n + 2
4. n + 3

The sum of the first 3 integers is equal to the 4th:
n + n + 1 + n + 2 = n + 3

Simplify by grouping like terms:
(n + n + n) + (1 + 2) = n + 3
3n + 3 = n + 3
3n = n
n = 0

n = 0
n + 1 = 1
n + 2 = 2
n + 3 = 3

Check our work:
0 + 1 +2 ? 3
3 = 3

Our final answer is (0, 1, 2, 3}