4 adults and 3 children cost $40. Two adults and 6 children cost $38 | MathCelebrity Forum

4 adults and 3 children cost $40. Two adults and 6 children cost $38

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4 adults and 3 children cost $40. Two adults and 6 children cost $38

Givens and Assumptions:
  • Let the number of adults be a
  • Let the number of children be c
  • Cost = Price * Quantity
We're given 2 equations:
  1. 4a + 3c = 40
  2. 2a + 6c = 38
We can solve this system of equations 3 ways
No matter what method we use, we get:
  • a = 7
  • c = 4
 
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