line equation

does the point (3,0) line on the line y=3x Substitute the x value of (x,y) = (3,0) into y = 3x: y = 3(3) y = 9 Since y = 9 and y <> 0, then no, this point does not lie on the line

the equation of a line is y = mx + 4. find m if the line passes through (-5,0) Plug in our numbers of x = -5, and y = 0: -5m + 4 = 0 To solve for m, we plug in this equation into our search engine and we get: m = 0.8 or 4/5 so our line equation becomes: y = 4/5x + 4

Find a linear function f, given f(16)=-2 and f(-12)=-9. Then find f(0). We've got 2 points: (16, -2) and (-12, -9) Calculate the slope (m) of this line using: m = (y2 - y1)/(x2 - x1) m = (-9 - -2)/(-12 - 16) m = -7/-28 m = 1/4 The line equation is denoted as: y = mx + b Let's use the first...

If the equation of a line passes through the points (1, 3) and (0, 0), which form would be used to write the equation of the line? Typing (1,3),(0,0) into the search engine, we get a point-slope form: y - 3 = 3(x - 1) If we want mx + b form, we have: y - 3 = 3x - 3 Add 3 to each side: y = 3x