If f(x) = ax^2 + bx + c and f(0) = 1 and f(-1) = 3, what is a - b
Evaluate f(0)
f(0) = a(0^2) + b(0) + c
f(0) = a(0) + b(0) + c
f(0) = c
Since f(0) = 1, we have
c = 1
Evaluate f(-1)
f(-1) = a(-1^2) + b(-1) + c
f(-1) = a(1) - b + c
f(-1) = a - b + c
Since f(-1) = 3, we have:
a - b + c = -3...